Answer to Question #71131 in General Chemistry for Christopher Ogden
2Ca(s)+O2(g) → 2CaO(s)
ΔH∘rxn= -1269.8 kJ; ΔS∘rxn= -364.6 J/K
Part A
Calculate the free energy change for the reaction at 27 ∘C.
1
2017-11-18T12:45:07-0500
∆G=∆H-T∆S
T = 27oC = 300.15 K
∆G=-1269.8 kJ-300.15K×(0.3646 kJ/K)=-1379 kJ
Answer: -1379 kJ
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