Give two differences that you would observe in the electrolytic cell if copper electrode was made the anode and graphite electrode was made the cathode
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Expert's answer
2017-11-15T12:56:06-0500
(P1*V1) / T1 = (P2*V2) / T2 756 mmHg = 100791.432 Pa 508 mmHg = 67727.576 Pa 30 C = 303 K -31 C = 242 K (100791.432 Pa * 0.33 m3) / 303 K = (V2 * 67727.576 Pa) / 242 K 109.772 = V2*279.866 V2= 2.549 L Answer: V= 2.549 L
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