Question #71075
When solid ammonium chloride dissociates at a certain temperature in a 0.500dm3 container, ammonia and hydrogen chloride are formed
NH4Cl --> NH3 + HCl
The initial amount of ammonium chloride was 1.00mol, and when the system had reached equilibrium there was a 0.300mol of ammonium chloride
What is the numerical value of Kc for this reaction under these conditions?
NH4Cl --> NH3 + HCl
The initial amount of ammonium chloride was 1.00mol, and when the system had reached equilibrium there was a 0.300mol of ammonium chloride
What is the numerical value of Kc for this reaction under these conditions?
Expert's answer
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#339914 on Dec 2023
#339914 on Dec 2023
Comments
Dear Ted, Thank You
Your answer is incorrect your mistake being: NH4Cl is in solid form hence it can't be included in the Kc Expression. NH4Cl(s) ----> NH3(g) + HCl(g) The answer in the mark scheme is 1.96