Answer to Question #71044 in General Chemistry for Aly

Question

How would you prepare a 0.138 m solution of FeBr3 from 900 g of water?

Answer 1

CM (FeBr3) = n(FeBr3) / V (solution)
V(H2O) = 900 mL = 0.9 L = V (solution)
n(FeBr3) = CM (FeBr3) x V (solution) = 0.138 mol/L x 0.9 L = 0.1242 mol
m(FeBr3) = n(FeBr3) x M(FeBr3) = 0.1242 mol x 296 g/mol = 36.76 g
You need to dissolve 36.76 g of FeBr3 in 900 g of water