How many liters of air will burn 30 liters of methane?
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Expert's answer
2017-11-01T14:10:07-0400
〖CH〗_4+〖2O〗_2→〖CO〗_2+〖2H〗_2 O ν=V/V_m ⇒ν~V V(O_2 )=2V(〖CH〗_4 )=30∙2=60 l. Air contains 21% O_2 by volume. V(air)=V(O_2 )/0.21=285.7≈286 l. Answer 286 l.
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