Answer to Question #70572 in General Chemistry for dog

Question

When 57.3 g of calcium is reacted with nitrogen gas, 30.0 g of calcium nitride is produced.
Slove 3Ca(s)+N2(g)→Ca3N2(s)

Answer 1

Molar mass of calcium nitride: M(Ca 3 N 2 )=148.2 g/mol
So, 30.0 / 148.2 = 0.2 mol of Ca 3 N 2 was formed.
The same amount of nitrogen reacted.
Mass of nitrogen: 28 x 0.2 = 5.6 g
Volume of nitrogen: 22.4 x 0.2 = 4.48 l
Answer:
5.6 g (4.48 l) of nitrogen reacted