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Answer to Question #70487 in General Chemistry for Sarah Frank

Question #70487
How much oxygen gas in grams can be prepared from 55.0 g of potassium chlorate?
1
Expert's answer
2017-10-09T14:42:06-0400
2KClO3 = 3KCl + 3O2
m(O2)= (55/2)*3 = 82,5 g

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