Question #70177
You will need to make four dilutions of the 0.40 M Cu(NO3)2 stock solution. determine the volume of Cu(NO3)2 stock solution and volume of H2O needed to make 10.00 mL of four solutions with concentrations between .200 M and 0.0250 M.
What threw me off here is that that the solution of H2O and CU(NO3)2 must be 10.00 mL.
What threw me off here is that that the solution of H2O and CU(NO3)2 must be 10.00 mL.
Expert's answer
0.200 M – 9.375 ml of 0.40 M + 9.375 ml of distilled water
↓ 8.75 ml
0.100 M – 8.75 ml of 0.200 M + 8.75 ml of distilled water
↓ 7.5 ml
0.050 M – 7.5 ml of 0.100 M + 7.5 ml of distilled water
↓ 5 ml
0.025 M – 5 ml of 0.050 M solution + 5 ml of distilled water
↓ 8.75 ml
0.100 M – 8.75 ml of 0.200 M + 8.75 ml of distilled water
↓ 7.5 ml
0.050 M – 7.5 ml of 0.100 M + 7.5 ml of distilled water
↓ 5 ml
0.025 M – 5 ml of 0.050 M solution + 5 ml of distilled water
