Answer to Question #69835 in General Chemistry for sharmaake
how many moles are in 87.6 g of aluminium sulphate, A1(SO4)3(K)
1
2017-08-28T10:08:07-0400
M(Al2(SO4)3)= 342.15 g/mol
n=m/M=(87.6 g)/(342.15 g/mol)=0.256 mol≅0.3 mol
Answer
In the anhydrous aluminum sulfate must be 0.3 moles.
Need a fast expert's response?
Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Learn more about our help with Assignments:
Chemistry
Comments
Leave a comment