Answer to Question #68896 in General Chemistry for chloe

Question #68896
a mixture of 0.100 mol of NO, 0.050 mol of H2 and 0.10 mol H2O is placed in a 1.0L vessel. the follwing equilibrium is established 2NO(g) + 2H2(g) ⇌ N2)g) + 2H2O(g) at equilibrium [NO]= 0.062M.
a. calculate the equilibrium concentration of H2, N2 and H2O.
b. calculate the Kc for the reation
1
Expert's answer
2017-06-19T06:12:09-0400
Answer
[H₂]=0.988M
[N₂]=0.019M
[H₂O]=0.062M
K=[H₂O]² [N₂]/[NO]²[H₂]²=0.062²*0.019/0.062²*0.088²=2.45

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