Answer to Question #68594 in General Chemistry for Zac

Question

A 40.8 mol sample of methane gas CH​4(g) is placed in a 1020 L container at 298 K. What is the pressure, in atm of the methane gas?

Answer 1

ollowing the Ideal gas law:
pV=nRT
where R is gas constant and equal to 0.0821 L·atm·K-1·mol-1
For this case, pressure in atm have been equal to:
p=nRTV=40.8 (mol)∙0.0821 (L∙atm∙K-1∙mol-1)∙298 (K)/ 1020 (L)=0.979 atm
Answer: the methane’s pressure in container is 0.979 atm