Answer to Question #68077 in General Chemistry for Charlotte Groves

Question

if 100.0 g of hot copper shot is placed in 100.0 g of water at 20.0 degrees celcius and the final temperature of the water/ shot mix is to 30.0 degrees celcius, what was the original temperature of the copper shot? (SHcopper= .385 J/g K)

Answer 1

qw = 4.18 J/g·°C × 100 g × (30 – 20°C) = 4180 J
-4180 J = 100 g × 0.385 J/g K × (30 – x)
x = 138.57°C

Answer: T(copper shot) = 138.57°C