Answer to Question #66363 in General Chemistry for Jadan Bostick

Question

Find the mass in grams of 2.00 x 1023 molecules of C10H15O.

Answer 1

Solution:
N = 2.00 ∙ 1023 molecules;
NA = 6.02 ∙ 1023 mol-1;
M (C10H15O) = 12 ∙ 10 + 1 ∙ 15 + 16 ∙ 1 = 151 g ∙ mol-1;
n=N/N_A ;
n=(2.00 ∙ 〖10〗^23 )/(6.02 ∙ 〖10〗^23 )=0.33 mol;
n=m/M;
m=n∙M=0.33∙151=49.83 g.
Answer: m (C10H15O) = 49.83 g.