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Answer to Question #65916 in General Chemistry for Tamera Prather
Question #65916
How many grams of potassium phosphate will be formed upon the complete reaction of 30.7 grams of phosphoric acid with excess potassium hydroxide
Expert's answer
H₃PO₄+3KOH=K₃PO₄+3H₂O
1MolH₃PO₄ -> 1Mol K₃PO₄
V(H₃PO₄)=m/M=30.7g/98g/Mol=0.313Mol
V(K₃PO₄)=0.313Mol
m(K₃PO₄)=V*M=0.313Mol*212g/Mol=66.36g
1MolH₃PO₄ -> 1Mol K₃PO₄
V(H₃PO₄)=m/M=30.7g/98g/Mol=0.313Mol
V(K₃PO₄)=0.313Mol
m(K₃PO₄)=V*M=0.313Mol*212g/Mol=66.36g
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