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Answer to Question #65784 in General Chemistry for davie
Question #65784
how many grams of copper metal are present in a 4.15 grams sample of copper (11) fluoride dihydrate?
Expert's answer
CuF2x2H 2 O
M(CuF2x2H 2 O) = 64 + 19x2 + 2x18 = 138 g/mol
64 g Cu ‒ 138 g CuF2x2H 2 O
X g Cu ‒ 4.15 g CuF 2x2H 2 O
X = 1.92 g Cu
Answer: m(Cu) = 1.92 g
M(CuF2x2H 2 O) = 64 + 19x2 + 2x18 = 138 g/mol
64 g Cu ‒ 138 g CuF2x2H 2 O
X g Cu ‒ 4.15 g CuF 2x2H 2 O
X = 1.92 g Cu
Answer: m(Cu) = 1.92 g
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