how many grams of oxygen are produced when 0.250 mol NO2 is formed?
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Expert's answer
2017-02-15T07:23:43-0500
Solution: M (O2) = 32 g/ mol n (NO2) = 0.250 mol Looking at the reaction you see that there is x times as much mol NO2. Need a reaction in which NO2 is formed (A(s)--->xNO2(g)+ yC(g)) O2= 0.25/x = 0.25/x mol. The answer in grams: 0.25/x mol * 32g / mol= (8 / x) grams Answer: (8 / x) grams
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