Answer to Question #65290 in General Chemistry for Sarah
What mass of ethanol is needed to create 2.5 gram of ethanoic acid (CH3COOH)? assume the ratio of ethanol to ethanoic acid needed is 1:1
1
2017-02-15T07:22:51-0500
m(CH3CH2OH) = 2,5g
n(CH3CH2OH) : n(CH3COOH) = 1: 1
m(CH3COOH) = ?
X g 2.5g
CH3CH2OH → CH3COOH
46 g/moll 60 g/moll
46g (CH3CH2OH) ─ 60g (CH3COOH)
X g (CH3CH2OH) ─ 2,5g (CH3COOH)
2,5×46
60
X = = 1,92g.
Answer: 1,92g. (CH3CH2OH)
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