1. m(H₂O)=₰*V=1g/ml*150ml=150g
n(C₆H₁₂O₆)=m(C₆H₁₂O₆)/M(C₆H₁₂O₆)=14,7g/180g/Mo=0,0817Mol
m´= n(C₆H₁₂O₆)/m(H₂O)=0,0817/0,150=0,54Mol/kg
Δt=K*m´; Δt=0,512*,05447=0,279ᵒC
Answer A
2. During the rule of the cross
9Mol(H₂SO₄) 1,25parts
1,25Mol 7,2parts
1Mol(H₂O) 7,75parts
6,5:7,2=0,903ml
Answer D
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