Answer to Question #64919 in General Chemistry for Mai

Question

If 45.00 mL of 2.00 M nitric acid is mixed with110.00 mL of 2.75 M calcium hydroxide identify the limiting reactant

Answer 1

2HNO3 + Ca(OH)2 -> Ca(NO3)2 + 2H2O
n(HNO3) = 0.045 L -> 2.00 M = 0.09 mole
n(Ca(OH)2) = 0.11 L -> 2.75 M = 0.3025 mole
2 mole HNO3 ‒ 1 mole Ca(OH)2
0.09 mole HNO3 ‒ x mole Ca(OH)2
x = 0.045 mole Ca(OH)2
HNO3 ‒ limiting reactant