Answer to Question #63745 in General Chemistry for marissa
how much heat is needed to warm 250 g of water from 22 degrees C to 98 degrees C, given the specific heat capacity of water at 4.18J/g degree C?
1
2016-12-01T14:09:15-0500
q = m x C xΔT
q = 250g x 4.18J/goC x (98 – 22)oC
q = 79.4 kJ
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