Calculate the pH change when 10. mL of 3.0 M HCl are added to 500. mL of the following A ) pure water B) aqueous solution of 3.0g of formic acid C) aqueous solution of 4.0g potassium formate D) aqueous solution containing 3.0 g of formic acid and 4.0 g of potassium formate.
Answer to each should consist of pH of each and the final pH after addition of HCl in order to find the CHANGE in pH. I have answered what i can:
a) pure water: pH 7 final pH : 1.22 change= -5.78
b) formic acid : pH 2.32 ?? final pH (dictated by stronger acid so) : 1.22 change: = -1.1
c) potassium formate: pH 8.87?? final pH: 3.5 ??? change: -5.37 ??
d) buffer: pH 3.61 ??? dont really understand this part.
The answer to the question is available in the PDF file https://www.assignmentexpert.com/https://www.assignmentexpert.com/homework-answers/chemistry-answer-63744.pdf
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
Comments
Leave a comment