Answer to Question #63235 in General Chemistry for Daniel sevigny

Question

What would Nd(OH)3.xH2O and Dy(OH)3.xH2O be calculated as to get the reaction in equation? or are the 2 equations already balanced and you just put Nd and Dy together in beginning of the sequence?

Answer 1

There is no any reaction or equation. You just written two formulas of neodymium and dysprosium hydroxides. These are quite reactive metals themselves and both will form highly reactive common hydroxides. Neodymium will also react with water itself - 2Nd + 6H2O = 2Nd(OH)3 + 3H2. Dysprosium will easily react with mineral acids - 2Dy + 6H+ = 2Dy3+ + 3H2. However, two hydroxides will not form any compound in the water solution. They can only be co precipitated together in form of mixed hydroxide.