According to the following reaction, how many grams of bromine monochloride will be formed upon the complete reaction of 26.6 grams of chlorine gas with excess bromine?
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Expert's answer
2016-10-19T13:53:09-0400
The equation for this reaction is: Br2 + Cl2 → 2BrCl The number of moles of chlorine gas equals: ν(Cl2) = m(Cl2)/Mr(Cl2) = 26.6 g / (2×35.5 g mol-1) = 0.3746 mol According to the equation the amount of formed BrCl is in two times more than that for Cl2. Thus, ν(BrCl) = 2ν(Cl2) = 0.7493 mol And its mass is: m(BrCl) = ν(BrCl)×Mr(BrCl) = 0.7493 mol × 115 g mol-1 = 86.17 g
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