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Answer to Question #62394 in General Chemistry for Lauren Sutherland
Question #62394
Problem 4.111 (Chapter 4)
The average concentration of gold in seawater is 100 fM (femtomolar).
1)Given that the price of gold is $1764.20 per troy ounce (1 troy ounce = 31.103 g), how many liters of seawater would you need to process to collect $6000 worth of gold, assuming your processing technique captures only 50 % of the gold present in the samples?
The average concentration of gold in seawater is 100 fM (femtomolar).
1)Given that the price of gold is $1764.20 per troy ounce (1 troy ounce = 31.103 g), how many liters of seawater would you need to process to collect $6000 worth of gold, assuming your processing technique captures only 50 % of the gold present in the samples?
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