A student has 15.0 mL of a 0.256 M phosphate solution. The student then adds excess
ammonium (NH4
+
) and magnesium (Mg2+) to the solution under slightly basic conditions.
Phosphate becomes HPO4
2-
under these conditions and reacts with the NH4
+
, Mg2+ and water to
produce 0.3005 g of struvite. Calculate the Percent Yield of Struvite.
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