Question

Timothy has 1 gallon of 6% bleach, assume 94% is water. Timothy decides to dilute the bleach separately. Timothy pours 10mL+0.1, 9mL+0.1, 8mL+0.1, 7mL+0.1, 6mL+0.1, and 1mL+0.1, of the bleach into 6 different containers and then fills the difference to 10mL with water. The density of the bleach is 1.11 g/cm3, and the 10mL is measured in a graduated cylinder. Calculate the new concentration, in moles per decimeter cubed, of the bleach in each container.

Answer 1

Answer on Question#61318 – Chemistry – General chemistry

Answer: Timothy has 1 gallon of 6% bleach, assume 94% is water. Timothy decides to dilute the bleach separately. Timothy pours 10mL+0.1, 9mL+0.1, 8mL+0.1, 7mL+0.1, 6mL+0.1, and 1mL+0.1, of the bleach into 6 different containers and then fills the difference to 10mL with water. The density of the bleach is 1.11 g/cm³, and the 10mL is measured in a graduated cylinder. Calculate the new concentration, in moles per decimeter cubed, of the bleach in each container.

Solution:

The chemical formula of bleach is NaClO. M(NaClO) = 74.5 g/mol

1 gallon = 378.412 dm³ = 378412 cm³

m(bleach) = 378412 cm³ · 1.11 g/ml = 420037.32 g

m(NaClO without water) = 420037.32 g · 0.06 = 25202.24 g

n(NaClO) = $\frac{25202.24\ g}{74.5\ g/mol} = 338.29\ mol$;

$C_0(\mathrm{NaClO}) = \frac{338.29\ mol}{378.412\ dm^3} = 0.894\ \mathrm{mol}/\ \mathrm{dm}^3$;

$C_{\text{new}} = \frac{C_0 V_0}{V_{\text{new}}}$, Error(%) = $\frac{0.1}{V_0} \cdot 100\%$;

Error(mol/dm³) = $\frac{\text{Error}(\%) \cdot C_{\text{new}}}{100}$

Answer:

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