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Answer to Question #60795 in General Chemistry for Kelia
Question #60795
if a 90.6 ml sample of gas has a partial pressure of 763.75 mmHg at 23.00 xelcius how many moles of gas are present
Expert's answer
PV = nRT, or
n = RT/PV
Than
n = 8.314*(273+23)/90.6*10-6*133.32*763.75 = 266.76 mol
n = RT/PV
Than
n = 8.314*(273+23)/90.6*10-6*133.32*763.75 = 266.76 mol
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