Question #59747

Explain the effect on equilibrium of the formation of HI from H2 reaction with I2 by
Increasing temperature
Increasing pressure by decreasing the volume
Decreasing concentration of hydrogen
Increasing the concentration of iodine
Adding a catalyst

Expert's answer

Answer on Question #59747, Chemistry / General Chemistry

Explain the effect on equilibrium of the formation of HI from H2\mathrm{H}_2 reaction with I2\mathrm{I}_2 by

- Increasing temperature

- Increasing pressure by decreasing the volume

- Decreasing concentration of hydrogen

- Increasing the concentration of iodine

- Adding a catalyst

Increasing temperature

H2(g)+I2(g)2HI(g)\mathrm{H}_{2(\mathrm{g})} + \mathrm{I}_{2(\mathrm{g})} \leftrightarrow 2\mathrm{HI}_{(\mathrm{g})}


endothermic reaction, ΔH>0\Delta \mathrm{H} > 0

With increasing temperature, the equilibrium shifts to the side of the endothermic reaction

the equilibrium shifts to the right ( → )

Pressures of gases are increased

when the pressure increases, the equilibrium shifts toward smaller volume


2V2V2\mathrm{V} \rightarrow 2\mathrm{V}


It does not affect the equilibrium displacement

Decreasing concentration of hydrogen

H2(g)+I2(g)2HI(g)\mathrm{H}_{2(\mathrm{g})} + \mathrm{I}_{2(\mathrm{g})} \leftrightarrow 2\mathrm{HI}_{(\mathrm{g})}v=k[H2][I2]v = k \cdot [\mathrm{H}_2] \cdot [\mathrm{I}_2]


the equilibrium shifts to the left ( ← )

Increasing the concentration of iodine

H2(g)+I2(g)2HI(g)\mathrm{H}_{2(\mathrm{g})} + \mathrm{I}_{2(\mathrm{g})} \leftrightarrow 2\mathrm{HI}_{(\mathrm{g})}v=k[H2][I2]v = k \cdot [\mathrm{H}_2] \cdot [\mathrm{I}_2]


the equilibrium shifts to the right ( → )

Adding a catalyst

It does not affect the equilibrium displacement

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