Question

. If 60.0 mL of water were added to 80.0 mL of a 0.500 M sodium carbonate, Na2CO3, solution, what would the
final molarity be? (Hint – what is the total new volume?)

Answer 1

Question #59543, Chemistry / General Chemistry

If $60.0~\mathrm{mL}$ of water were added to $80.0~\mathrm{mL}$ of a $0.500\mathrm{M}$ sodium carbonate, Na2CO3, solution, what would the final molarity be? (Hint – what is the total new volume?)

Answer

$$\begin{array}{l} C_{1} \cdot V_{1} = C_{2} \cdot V_{2} \\ V_{\text{final}} = 80 + 60 = 140~\mathrm{mL} \\ 0.5\,M \cdot 80~\mathrm{mL} = C_{x} \cdot 140~\mathrm{mL} \\ C_{x} = \frac{0.5 \cdot 80}{140} = 0.286\,M \\ \end{array}$$

Answer: $[Na_2CO_3] = 0.286\,M; V = 140~\mathrm{mL}$

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