How much ammonia (NH3) could be melted by the addition of 3.5 kJ of heat, if the temperature of the liquid is at the melting point? (ΔHfus=5.66 kJ/mol)
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Expert's answer
2016-04-25T12:18:05-0400
Q=ΔHfus·n n=m/M M (NH3)=17 g/mol m (NH3)=(Q·M)/ΔHfus m (NH3)=(3.5·17)/5.66=10.5 g
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