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Answer to Question #59226 in General Chemistry for Daniela
Question #59226
A sample of 0.255 mole of gas has a volume of 0.748L at 301K, Calculate the pressure of the gas.
(PV = nRT) (R=0.0821L x atm/ mol x K)
(PV = nRT) (R=0.0821L x atm/ mol x K)
Expert's answer
PV = nRT, or
P = nRT/V
Therefore,
P = 0.255*0.0821*301/0.748 = 8.425 atm
Answer: 8.425 atm
P = nRT/V
Therefore,
P = 0.255*0.0821*301/0.748 = 8.425 atm
Answer: 8.425 atm
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