Question

What concentration of 250. mL of calcium chloride and silver nitrate are needed to theoretically produce 3.75 grams of precipitate? How many grams of calcium chloride and silver nitrate are needed to make each of the solutions?

Answer 1

Question # 59170, Chemistry / General Chemistry | for completion

What concentration of 250. mL of calcium chloride and silver nitrate are needed to theoretically produce 3.75 grams of precipitate? How many grams of calcium chloride and silver nitrate are needed to make each of the solutions?

Answer

Y, g X, g 3.75 g

$$CaCl_2 + 2\ AgNO_3 \rightarrow Ca(NO_3)_2 + 2\ AgCl$$

111 g/mole 2*170 g/mole 2*143.5 g/mole

X (AgNO₃) = 4.443 g

Y (CaCl₂) = 1.450 g

$$C(\mathrm{AgNO_3}) = \frac{m}{Mr \cdot V} = \frac{4.443}{170 \cdot 0.25} = 0.1045\ M$$ $$C(CaCl_2) = \frac{m}{Mr \cdot V} = \frac{1.45}{111 \cdot 0.25} = 0.0523\ M$$

Answer: m (AgNO₃) = 4.443 g and m (CaCl₂) = 1.450 g and concentration C_M (AgNO₃) = 0.1045 M

C_M (CaCl₂) = 0.0523 M

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