Question #59006
The alcohol in "gasohol" burns according to the following equation.
C2H6O+3O2----> 2CO2+3H2O
If 25 mol of C2H5OH burns this way, how many moles of oxygen are needed
C2H6O+3O2----> 2CO2+3H2O
If 25 mol of C2H5OH burns this way, how many moles of oxygen are needed
Expert's answer
Solution:
The amount of substance of Oxygen:
n(O2) = 3 mol *25 mol/1 mol = 75 mol
Answer:
By the reaction 75 mol of oxygen are needed.
The amount of substance of Oxygen:
n(O2) = 3 mol *25 mol/1 mol = 75 mol
Answer:
By the reaction 75 mol of oxygen are needed.
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#339914 on Dec 2023
#339914 on Dec 2023
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