Question #58739

A 33.00 mL sample of an H2SO4 solution of unknown concentration is titrated with a 0.1222 M KOH solution. A volume of 40.22 of 40.22 mL of KOH was required to reach the equivalence point.

What is the concentration of the unknown H2SO4 solution?

express your answer in 4 significant figures
1

Expert's answer

2016-03-29T11:20:04-0400

Question #58739, General chemistry

A 33.00 mL sample of an H2SO4 solution of unknown concentration is titrated with a 0.1222 M KOH solution. A volume of 40.22 of 40.22 mL of KOH was required to reach the equivalence point.

What is the concentration of the unknown H2SO4 solution?

Solution

H2SO4+2KOH=K2SO4+2H2O\mathrm{H_2SO_4} + 2\mathrm{KOH} = \mathrm{K_2SO_4} + 2\mathrm{H_2O}n(KOH)=Vc=40.220.1222=4.9149 (mmol)n(\mathrm{KOH}) = V \cdot c = 40.22 \cdot 0.1222 = 4.9149 \text{ (mmol)}n(H2SO4)=2n(KOH)=9.8298 (mmol)n(\mathrm{H_2SO_4}) = 2 \cdot n(\mathrm{KOH}) = 9.8298 \text{ (mmol)}c(H2SO4)=n/V=9.8298/33=0.2978 Mc(\mathrm{H_2SO_4}) = n/V = 9.8298 / 33 = 0.2978 \text{ M}

Answer

c(H2SO4)=0.2978 Mc(\mathrm{H_2SO_4}) = 0.2978 \text{ M}


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