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Answer to Question #58269 in General Chemistry for sara
Question #58269
If 0.106 moles of zinc reacts with excess lead(IV) sulfate, how many grams of zinc sulfate would be produced?
Expert's answer
2Zn + Pb(SO4)2 = 2ZnSO4 + Pb
N(ZnSO4)=N(Zn)= 0.106 moles.
m(ZnSO4)=0.106* 161.45=17.11g
N(ZnSO4)=N(Zn)= 0.106 moles.
m(ZnSO4)=0.106* 161.45=17.11g
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Dear Laura Questions in this section are answered for free. We work on all questions and publish answers after verification. There is no guarantee of answering certain question but we are doing our best. Although if you have serious assignment that requires large amount of work and hence cannot be done for free you can submit it as assignment and our experts will surely assist you.
where does the 161.45 come from?
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