A 41.1-mL sample of H2 at STP would contain how many grams of hydrogen?
1
Expert's answer
2016-02-23T00:00:54-0500
The volume of 1 mole of gas under normal conditions is equal to 22.4 liters. The molar mass of hydrogen is equal to 2 g / mol. Thus, the weight of 22.4 liters of hydrogen is equal to 2 grams 41.1 mL = 0.0411 liters. Then the mass of 41.1 ml of hydrogen is 2 * 0.0411 / 22.4 = 0.00367 g = 3.67*10–3 g.
Answer. Weight of 41.1 ml of hydrogen is 3.67*10–3 g
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment