30cm of hydrogen diffuses out in 2 seconds. How long will it take 90cm of oxygen to diffuse out under the same conditions
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Expert's answer
2016-02-12T05:34:01-0500
According to Graham's law: rateH22 x MH2 = rateO22 x MO2 M (H2)=2 g/mol M (O2) = 32 g/mol RateH2: 30/2=15 cm/s. RateO2=(rateH22 x MH2 )/MO2 RateO2=(152 x 2 )/32 = 14.1 cm/s So that 90 cm of oxygen under the same conditions will be diffused during: T=90/14.1=6.4 s
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