Question #57727
If a manufacturing company reacts 25 kilograms of 52.5% calcium nitrate ore with excess ammonium phosphate, how many grams of calcium phosphate are produced?
Expert's answer
3Ca(NO3)2->Ca3(PO4)2
m(CaNO3)=25*1000*0.525=13125 g
N(Ca(NO3)2)=80 moles
N(Ca3(PO4)2)= 80/3 = 26.67 moles; m(Ca3(PO4)2) = 8270 g
m(CaNO3)=25*1000*0.525=13125 g
N(Ca(NO3)2)=80 moles
N(Ca3(PO4)2)= 80/3 = 26.67 moles; m(Ca3(PO4)2) = 8270 g
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#340153 on Dec 2023
#340153 on Dec 2023
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