If a manufacturing company reacts 25 kilograms of 52.5% calcium nitrate ore with excess ammonium phosphate, how many grams of calcium phosphate are produced?
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Expert's answer
2016-02-12T00:01:01-0500
3Ca(NO3)2->Ca3(PO4)2 m(CaNO3)=25*1000*0.525=13125 g N(Ca(NO3)2)=80 moles N(Ca3(PO4)2)= 80/3 = 26.67 moles; m(Ca3(PO4)2) = 8270 g
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