Question

Calcium chloride, CaCl2, is commonly used as an electrolyte in sports drinks and other beverages, including bottled water. A solution is made by adding 5.00 g of CaCl2 to 60.0 mL of water at 25∘C. The density of the solvent at that temperature is 0.997 g/mL. Calculate the mole percent of CaCl2 in the solution.
Express your answer as a percent to three significant figures.
This is what they are looking for: mole/mole percent (mol/mol) =???
I entered this....and it was wrong?
ANSWER 1: Deduction: -3%
mole/mole percent (mol/mol) =
1.49%
Thanks!