The gaseous hydrocarbon butane, C4H10, burns according to the following equation:
2C4H10(g)+13O2(g)→8CO2(g)+10H2O(g)
If the reaction in part c produces 130 g of CO2, what is the percent yield of CO2 for the reaction?
Express your answer with the appropriate units.
The percent yield of CO2 = ???
1
Expert's answer
2015-10-22T08:55:48-0400
Percent yield = actual yield / theoretical yield * 100% Actual yield (CO2) = 130 g Theoretical yield (CO2) = 168.7 g Percent yield (CO2) = 130 g / 168,7 g * 100% = 77 %.
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