Answer to Question #55703 in General Chemistry for sue

Question

The gaseous hydrocarbon butane, C4H10, burns according to the following equation:
2C4H10(g)+13O2(g)→8CO2(g)+10H2O(g)
How many grams of O2 are needed to react completely with 23.5 g of C4H10?
Express your answer with the appropriate units.
m(O2) = ?????
Thank you so much!!

Answer 1

2C4H10(g) + 13O2(g) → 8CO2(g) + 10H2O(g)

m(O2) = M(O2)*n(O2)
n(O2) = (13/2)*n(CO2) = (13/2)*(m(CO2)/M(CO2)) = (13/2)*(23.5/58) = 2.63 mol
m(O2) = M(O2)*n(O2) = 32*2.63 = 84.28 g

Answer : m(O2) = 84.28 g