Now consider a situation in which 26.0 g of P4 is added to 59.0 g of Cl2, and a chemical reaction occurs. To identify the limiting reactant, you will need to perform two separate calculations:
1.Calculate the number of moles of PCl5 that can be produced from 26.0 g of P4 (and excess Cl2).
2.Calculate the number of moles of PCl5 that can be produced from 59.0 g of Cl2 (and excess P4).
Then, compare the two values. The reactant that produces the smaller amount of product is the limiting reactant.**answer to #1 is 0.839 moles...answer to #2 is 0.333 moles
Info needed:What mass of PCl5 will be produced from the given masses of both reactants?
Express your answer to three significant figures and include the appropriate units.
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
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