How many moles of PCl5 can be produced from 59.0 g of Cl2 (and excess P4)?
Express your answer to three significant figures and include the appropriate units.
1
Expert's answer
2015-10-20T04:21:33-0400
The balanced chemical eqiation is P4 + 10Cl2 = 4PCl5[sub] The mass of clorine is m(Cl[sub]2) = 59.0 g The amount of clorine is n(Cl2) = m(Cl2)/M(Cl2) = 59/70.906 = 0.832 mol The reacion stoichiometry shows that 10 moles of Cl2 yield 4 moles of PCl5; 0.832 of Cl2 yield x moles of PCl5 n(PCl5) = 4*0.832/10 = 0.333 mol
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