Answer to Question #55658 in General Chemistry for rachel

Question

Nitrogen gas reacts with hydrogen gas to produce ammonia.
N2(g)+3H2(g)→2NH3(g)
How many grams of H2 are needed to react with 3.40 g of N2?

Thanks for your help!!

Answer 1

The balanced chemical eqiation is
N₂(g)+3H₂(g)→2NH₃(g)
The mass of nitrogen is m(N₂) = 3.40 g
The amount of nitrogen is n(N₂) = m(N₂)/M(N_{2[]/sub) = 3.4/28.013 = 0.121 mol
The reacion stechiometry shows that we need 3 times more moles of hydrogen to react completely with this amount of nitrogen, or n(H[sub]2}) = 3x0.121 = 0.363 mol
The mass of hydrogen reqired is m(H₂) = n(H₂)M(H₂) = 0.363x2.016 = 0.732 g
Answer: 0.732 g