Question #55348

For a particular isomer of C8H18, the following reaction produces 5108.7 kJ of heat per mole of C8H18(g) consumed, under standard conditions.
What is the standard enthalpy of formation of this isomer of C8H18(g)?
1

Expert's answer

2015-10-09T03:40:47-0400

Answer on Question #55348 - Chemistry - General chemistry

Question:

For a particular isomer of C8H18C_8H_{18}, the following reaction produces 5108.7 kJ of heat per mole of C8H18(g)C_8H_{18}(g) consumed, under standard conditions. What is the standard enthalpy of formation of this isomer of C8H18(g)C_8H_{18}(g)?

Solution

C8H18(g)+25/2O2(g)=8CO2(g)+9H2O(g);ΔHrxn=5108.7kJΔHrxn=9ΔH(H2O)+8ΔH(CO2)ΔH(C8H18)ΔH(C8H18)=9ΔH(H2O)+8ΔH(CO2)ΔHrxnΔH(C8H18)=9(241.8)+8(393.5)+5108.7=215.5kJ/mol\begin{array}{l} C_8H_{18}(g) + 25/2 O_2(g) = 8CO_2(g) + 9H_2O(g); \quad \Delta H_{\text{rxn}} = -5108.7 \, \text{kJ} \\ \quad \Delta H_{\text{rxn}} = 9\Delta H(H_2O) + 8\Delta H(CO_2) - \Delta H(C_8H_{18}) \\ \quad \Delta H(C_8H_{18}) = 9\Delta H(H_2O) + 8\Delta H(CO_2) - \Delta H_{\text{rxn}} \\ \quad \Delta H(C_8H_{18}) = 9(-241.8) + 8(-393.5) + 5108.7 = -215.5 \, \text{kJ/mol} \end{array}


Answer: 215.5kJ/mol-215.5 \, \text{kJ/mol}

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