Question #55263

When lithium oxide (Li2O) is dissolved in water, the solution turns basic from the reaction of the oxide ion (O^2-) with water. Write the equation for this reactionand, identify the conjugate acid-base pairs.

Expert's answer

Answer on Question #55263 - Chemistry - General chemistry

Question:

When lithium oxide (Li2O)(\mathrm{Li}_2\mathrm{O}) is dissolved in water, the solution turns basic from the reaction of the oxide ion (O2−)(\mathrm{O}^{2-}) with water. Write the equation for this reaction and, identify the conjugate acid-base pairs.

Answer:

If we consider the formation of oxide ion we will have the following two reactions:

1. Dissociation of Li2O\mathrm{Li}_2\mathrm{O}

Li2O⇌2Li++O2−\mathrm {L i} _ {2} \mathrm {O} \rightleftharpoons 2 \mathrm {L i} ^ {+} + \mathrm {O} ^ {2 -}


2. Reaction between formed anion and water:


O2−+H2O⇌2OH−\mathrm {O} ^ {2 -} + \mathrm {H} _ {2} \mathrm {O} \rightleftharpoons 2 \mathrm {O H} ^ {-}


In this case for two reagents we will have to conjugated pairs:

1. O2−\mathrm{O}^{2-} (base) and OH−\mathrm{OH}^{-} (acid)

2. H2O\mathrm{H}_2\mathrm{O} (acid) and OH−\mathrm{OH}^{-} (base)



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