Question

Lead(II) carbonate decomposes to give lead (II) oxide and carbon dioxide: PbCO3 >>PbO + CO2
How many grams of lead(II) will be produced by the decomposition of 2.50 g of lead (II) carbonate?
How many moles of CO2 will be produced?

Answer 1

Answer on Question #55232 – Chemistry – Other

Question:

Lead(II) carbonate decomposes to give lead (II) oxide and carbon dioxide:

$$\mathrm{PbCO_3} \rightarrow \mathrm{PbO} + \mathrm{CO_2}$$

How many grams of lead (II) will be produced by the decomposition of 2.50 g of lead (II) carbonate?

How many moles of $\mathrm{CO_2}$ will be produced?

Answer:

$$v = \frac{m}{M}$$ $$v(\mathrm{PbCO_3}) = v(\mathrm{PbO}) = v(\mathrm{CO_2})$$ $$M(\mathrm{PbCO_3}) = 267.2\ \mathrm{g/mol}$$ $$M(\mathrm{Pb}) = 207.2\ \mathrm{g/mol}$$ $$m(\mathrm{Pb}) = \frac{2.50}{267.2} \cdot 207.2 = 1.94\ g$$ $$v(\mathrm{CO_2}) = \frac{2.50}{267.2} = 0.01\ mol$$

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