Question #54629
Find the number of joules needed to heat 37grams of water 78 degees C.
Expert's answer
To heat 1 g on 1 degree C we need 1 cal.
So to heat 37 g on 78 degrees C we need:
C=37*78=2886 cal.
1 cal.=4.184 J
So, 2886 cal.=2886*4.184=12075.024 J.
So to heat 37 g on 78 degrees C we need:
C=37*78=2886 cal.
1 cal.=4.184 J
So, 2886 cal.=2886*4.184=12075.024 J.
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#340153 on Dec 2023
#340153 on Dec 2023
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