Find the number of joules needed to heat 37grams of water 78 degees C.
1
Expert's answer
2015-09-10T10:07:49-0400
To heat 1 g on 1 degree C we need 1 cal. So to heat 37 g on 78 degrees C we need: C=37*78=2886 cal. 1 cal.=4.184 J So, 2886 cal.=2886*4.184=12075.024 J.
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