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Answer to Question #54304 in General Chemistry for prudence david
Question #54304
A proton with speed v perpendicular to a magnetic field B is experiences a force F. if the speed of the proton is doubled, the new force is
Expert's answer
The force acting on the moving charged particle with the velocity v and charge q is: F=qvB
Then, doubling the velocity leads doubling the force.
Then, doubling the velocity leads doubling the force.
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