Answer to Question #54304 in General Chemistry for prudence david

Question #54304
A proton with speed v perpendicular to a magnetic field B is experiences a force F. if the speed of the proton is doubled, the new force is
1
Expert's answer
2015-08-31T03:38:06-0400
The force acting on the moving charged particle with the velocity v and charge q is: F=qvB
Then, doubling the velocity leads doubling the force.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS