Question

In a standard volumetric analysis performed in a laboratory class involving potassium permanganate (158) and sodium oxalate (84)solution, the following titre values were obtained : 25.90; 26.50; 26.60 respectively. Determine the volume of the titrant

Answer 1

The volume of the titrant equals the average value of obtained titre:
V = (26.50 ml + 26.60 ml)/2 = 26.55 ml
The titre value of 25.90 ml is not counted, because it differs significantly from two other values (26.50 and 26.60).